Me postulé a través de un reclutador. El proceso tomó 3 semanas. Acudí a una entrevista en Meta en dic 2020
Entrevista
There is an initial call with an HR representative, followed by one phone-screen with an engineer. You are supposed to solve two 15-20 minute programming puzzles (though in my phone screen i was only asked to solve one somehow).
If you pass the phone screen - it is followed then by 3 additional programming interviews, each of which is of the same format (two 15-20 minute puzzles) and a behavioral interview.
Preguntas de entrevista [1]
Pregunta 1
Describe an implement an algorithm for finding a local minimum value in an array of numbers (a local minimum is a value where both neighbouring values are equal or larger).
Acudí a una entrevista en Meta (Londres, Inglaterra)
Entrevista
Generic LeetCode-style questions, many tagged as Meta, so extensive preparation is required to perform well in the technical interview. The experience varies significantly - some interviewers provide hints and guidance, while others expect candidates to solve problems independently with minimal assistance.
Spoke with interviewer over video conferencing. He was very communicative . He answered my questions. Asked me BFS question. A question that involved BFS search. Given a matrix, I am suppose to find a path from top left to down right.
Preguntas de entrevista [1]
Pregunta 1
A question that involved BFS search. Given a matrix, I am suppose to find a path from top left to down right.
The technical round hit me with a classic array manipulation problem: moving zeroes to the end without disrupting the order of non-zero elements. As I tackled it, I felt a wave of familiarity wash over me; I had just practiced a similar challenge on PracHub. The rest of the interview followed a straightforward path, with some easy behavioral questions sprinkled in. Overall, it felt very easy, but I wasn’t quite the right fit for what they needed, so I didn’t receive an offer.
Preguntas de entrevista [1]
Pregunta 1
Move zeroes in an array to the end while keeping non-zero element order, in place