How to reverse a int number and double number

Question

Anónimo · Accepted Answer

import java.math.BigDecimal;

public class ReversOfANumber {

    public void reverse(double d) {
        BigDecimal convert = BigDecimal.valueOf(d);
        int int_part = convert.intValue();
        BigDecimal dp = convert.remainder(BigDecimal.ONE);

        while (dp.remainder(BigDecimal.ONE).floatValue() > 0) {
            dp = dp.movePointRight(1);
        }
        int decimalPart = dp.intValue();

        int reverse_dp = reverse(decimalPart);
        int reverse_int = reverse(int_part);

        System.out.print(reverse_dp);
        System.out.print(".");
        System.out.print(reverse_int);
    }


    public int reverse(int a) {
        int r;
        int reverse = 0;
        while (a > 0) {
            r = a % 10;
            a = a / 10;
            reverse = reverse * 10 + r;
        }
        return reverse;
    }

    public static void main(String[] args) {
        ReversOfANumber r = new ReversOfANumber();
        System.out.println(r.reverse(1235));
        r.reverse(123.45);
    }
}

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