How to convert an Optional string to integer without throwing exception

Question

Anónimo · Accepted Answer

use  filter and map

Monis Yousuf · Answer

Well its pretty basic.
1. Convert String into character array.
2. Check if Array's length = 48 && intValue <= 57) {
					int numValue = values[intValue - 48];
					finalNumber += (numValue * Math.pow(10, power));
					power--;
				} else {
					System.out.println("Not a number");
					return;
				}
			}
			finalNumber *= multiplier;
			System.out.println(finalNumber);
		}

Monis Yousuf · Answer

Program
___________________________________________

int[] values = {0,1,2,3,4,5,6,7,8,9};
		
		String test = "-123";
		char[] arr = test.toCharArray();
		if(arr.length = 48 && intValue <= 57) {
					int numValue = values[intValue - 48];
					finalNumber += (numValue * Math.pow(10, power));
					power--;
				} else {
					System.out.println("Not a number");
					return;
				}
			}
			finalNumber *= multiplier;
			System.out.println(finalNumber);
		}

Anónimo · Answer

glassdoor not allowing to post full code.

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