Given two numbers a and b, we have an averaging function (a+b)/2. This function wont work under certain cases. I was supposed to tell the case, and also how to handle it.

Question

Given two  numbers a and b, we have an averaging function (a+b)/2. This function wont work under certain cases. I  was supposed to tell the case, and also how to handle it.

Anónimo · Accepted Answer

When a and b will be very large values, we would have an overflow. Hence we need to right shift a and b first , i.e a/2 and b/2 , and then add them. However, this wont work if both a and b are odd numbers. In case, if both are odd, then we need to add 1 to the final result 

eg : a = 5 =  101
       b = 3 =  011

    ( a >> 1)+ (b >> 1) = 3 . So we add 1 to it. Hence, answer is 4

Anónimo · Answer

Won't work if a and b are very large values.
We could do this instead: a + (b - a) / 2 or b + (a - b) / 2, depending on which one is greater.

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